Univ. of Wisconsin - Parkside
Math 301
October 15, 2025
Homework 9: Linear Transformations
Instructions. Assignments should be stapled and written clearly and legibly.
- Let \(T:V\to W\) be a linear transformation, and let
\(\{\bv_1,\bv_2,\ldots,\bv_n\}\) be a set of vectors that
spans \(V\). Prove that if $$
T(\bv_1)=T(\bv_2)=\cdots=T(\bv_n)=\mathbf{0}, $$ then
\(T(\bu)=\mathbf{0}\) for all vectors \(\bu\) in \(V\).
Hint. Use Theorem 2.1. -
Let \(T:V\to W\) be a linear transformation.
-
Suppose that \(\{\bv_1,\ldots,\bv_p\}\) is a linearly
dependent set of vectors in \(V\). Using the definition of
linear dependence and Theorem 2.1, prove that
\(\{T(\bv_1),\ldots,T(\bv_p)\}\) is linearly dependent in
\(W\).
Hint. Begin the proof as follows: ``Since \(\{\bv_1,\ldots,\bv_p\}\) is linearly dependent, there exist scalars \(c_1,\ldots,c_p\) which are not all zero for which \(c_1\bv_1+\cdots+c_p\bv_p=\mathbf{0}\).'' - Suppose that \(\{\bv_1,\ldots,\bv_p\}\) is a linearly independent set of vectors in \(V\). Is \(\{T(\bv_1),\ldots,T(\bv_p)\}\) necessarily linearly independent in \(W\)? Is yes, prove it. If no, give a counterexample.
-
Suppose that \(\{\bv_1,\ldots,\bv_p\}\) is a linearly
dependent set of vectors in \(V\). Using the definition of
linear dependence and Theorem 2.1, prove that
\(\{T(\bv_1),\ldots,T(\bv_p)\}\) is linearly dependent in
\(W\).
- Determine whether each of the following transformations
\(T\) is linear. Prove your answers.
- \(T:\bR^2\to \bR^2\) defined by \(T(\vtwo{x_1}{x_2})=\vtwo{4x_1-2x_2}{3|x_2|}\).
- \(T:\bR^2\to \bR^3\) defined by \(T(\vtwo{x_1}{x_2})=\vthree{x_1-2x_2}{x_1+3x_2}{3x_1-4x_2}\).
- \(T:P_2\to P_2\) defined by \(T(a+bx+cx^2)=a + b(x+1)+b(x+1)^2\).
-
Show that each of the following transformations \(T:\bR^2\to
\bR^2\) is linear by finding a matrix \(A\) such that
\(T(\bx)=A\bx\). Describe geometrically what each
transformation does.
- \(T(\vtwo{x_1}{x_2})=\vtwo{-x_1}{\pe x_2}\)
- \(T(\vtwo{x_1}{x_2})=\vtwo{x_2}{x_1}\)
- \(T(\vtwo{x_1}{x_2})=\vtwo{0}{x_2}\)
- \(T(\bx)=-\bx\)
- \(T(\bx)=\frac{1}{2}\bx\)